LOS ANGELES -- Australian star Andrew Bogut has inked a one-year deal with the Los Angeles Lakers, the player's agent said on Tuesday.
Bogut, 32, has been a free agent since parting with the Cleveland Cavaliers in March, when he sustained a broken leg on his debut for the club.
The deal, confirmed by agent David Bauman on Twitter, is reportedly worth $2.3 million (1.9 million euros) for the towering center.
Bogut endured a nomadic 2016-2017 season, starting out with the Dallas Mavericks where he averaged three points and 8.4 rebounds in 26 games.
He was later traded to the Philadelphia 76ers and then reached a buyout agreement in February which freed him to join the Cavaliers.
However his Cleveland career lasted just 58 seconds after a collision with Miami's Okaro White left him with a fractured tibia.
Bogut, the number one pick in the 2005 draft, was a member of the Golden State Warriors team which won the NBA Finals in 2015 and was a runner-up the following season.
Bogut's best season in a 13-year NBA career came in 2009-2010, when he averaged 15.2 points and 10.2 rebounds for the Milwaukee Bucks.
© Agence France-Presse
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